f(x)=3ln(2x+1)+4ln(x^2-4)

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Solution for f(x)=3ln(2x+1)+4ln(x^2-4) equation: 


Simplifying
f(x) = 3ln(2x + 1) + 4ln(x2 + -4)

Multiply f * x
fx = 3ln(2x + 1) + 4ln(x2 + -4)

Reorder the terms:
fx = 3ln(1 + 2x) + 4ln(x2 + -4)
fx = (1 * 3ln + 2x * 3ln) + 4ln(x2 + -4)
fx = (3ln + 6lnx) + 4ln(x2 + -4)

Reorder the terms:
fx = 3ln + 6lnx + 4ln(-4 + x2)
fx = 3ln + 6lnx + (-4 * 4ln + x2 * 4ln)
fx = 3ln + 6lnx + (-16ln + 4lnx2)

Reorder the terms:
fx = 3ln + -16ln + 6lnx + 4lnx2

Combine like terms: 3ln + -16ln = -13ln
fx = -13ln + 6lnx + 4lnx2

Solving
fx = -13ln + 6lnx + 4lnx2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = -13lnx-1 + 6ln + 4lnx

Simplifying
f = -13lnx-1 + 6ln + 4lnx

Reorder the terms:
f = 6ln + -13lnx-1 + 4lnx

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